Math, asked by hm1350971, 3 days ago

iv) The value of log (tan 1°) x log (tan 2°) x log (tan 3°) (tan 50°) = ... a) 1 b) 0 c) d) V3​

Answers

Answered by himanshu4569192
1

Answer:

I THINK (A) IS ANSWER.

Answered by arjunkrishnaks1
0

Answer:

b) 0

Step-by-step explanation:

We know that,

log 1 = 0

So, By Solving the given equation, we get:

log (tan 1°)  x  log (tan 2°)  x  log (tan 3°) (tan 50°)

⇒log (tan 1). log (tan 2). log (tan 3). (tan 50)

⇒0 . log tan2. log tan3. tan50   { by putting the value for log (tan1) = 0}  

⇒0    { Anything multiplied by 0 gives 0, Hence the entire terms became equal to 0 }

∴ log (tan 1°) x log (tan 2°) x log (tan 3°) (tan 50°) = 0

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