Math, asked by 0221, 8 months ago

iv) Touching the lines 4x – 3y + 10 = 0 and 4x – 3y – 30 = 0 and the centre lying on
2x + y = 0.

Answers

Answered by itzAashish
5

Answer:

The given tangents are parallel and therefore the distance between them

= 2r =

5

10−(−30)

=8∴r=4

Now the diameter 2x + y = 0 cuts the given line in the points P (-1, 2) and Q (3, -6) whose middle point is therefore the centre (1, - 2).

Hence its equation is (x−1)

2

+(y+2)

2

=4

2

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Answered by Anonymous
4

Answer:

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