iv) Touching the lines 4x – 3y + 10 = 0 and 4x – 3y – 30 = 0 and the centre lying on
2x + y = 0.
Answers
Answered by
5
Answer:
The given tangents are parallel and therefore the distance between them
= 2r =
5
10−(−30)
=8∴r=4
Now the diameter 2x + y = 0 cuts the given line in the points P (-1, 2) and Q (3, -6) whose middle point is therefore the centre (1, - 2).
Hence its equation is (x−1)
2
+(y+2)
2
=4
2
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Answered by
4
Answer:
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