Question

(iv) Two buildings are facing each other on a road of width 12 metres. From the ton
of the first building which is 10 metres high, the angle of elevation of the top
of the second is found to be 60°. What is the height of the second building?
LT​

Answer 1

Answer:

10+ 12√3

Step-by-step explanation:

tan60°= extra height of top building/width

extra height = width*tan60° = 12√3

total height = 10+ 12√3 = 30.785m approx

Answer 2

Step-by-step explanation:

tan 60°= p/b

√3=p/12

p=12√3

now height of second building is (10+p)

=(10+12√3)m

hope it helps!!!!