Math, asked by bhateanamikagmailcom, 2 months ago

(iv) Two fair dice are thrown simultaneously. Find the probability of getting: (a) sum of the score is exactly 7 (b) sum of the score is at the most 10​​

Answers

Answered by ItzAdityaKarn
0

Answer:

Sample space for total number of possible outcomes

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total number of outcomes =36

(i)

Favorable outcomes for sum as prime are

(1,1),(1,2),(1,4),(1,6),(2,3),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)

Number of favorable outcomes =15

Hence, the probability of getting the sum as a prime number. = 3615=125

(ii)

Favorable outcomes for total of atleast 10 are

(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)

Number of favorable outcomes =6

Hence, the probability of getting a total of atleast 10 = 366=61

(iii)

Favorable outcomes for a doublet of even number are

(2,2),(4,4),(6,

Answered by niteshshaw723
0

Answer:

b number is the answer of this question

Similar questions