Question

(iv) What is the sum of first 10 natural numbers?​

Answer 1

$\huge\mathcal\red{Answer}$

The series of first 10 natural numbers is an arithmetic progressions with first tern as 1 and common difference 1. So the sum of the series will be Sn = n/2 { 2a+ ( n-1 ) d } where n is the number of terms in the series, a is the first term and d is the common difference.

S10= 10/2 { 2(1) + ( 10-1 ) 1 }

= 5 ( 2+9)

= 5 ( 11 )

= 55

Answer 2

Natural Nunbers - 1,2,3,4,5,6,7,8,9,10.

Sum-

1+2+3+4+5+6+7+8+9+10= 55