Question

iv) What quantity of 'O', require
in 64 gr of sulphur completely.​

Answer 1

Answer:

S+O2---->SO2

1 mole of S will require one mole of O2..

64 gram(64/32) =2moles of S will require two moles of O2..

[where 32 is the molecular weight of both Sulphur and Oxygen molecule]...

This, 2×32g of O2 is required

=64g...

Hope it helps, buddy

Answer 2

Answer:

I am soory I don't know the answer