Question

(iv) What should be added with the numbers of CRPF soldiers and the number of bikers so t
their maximum number of column is equal to the maximum number of column of army troop
(a) 4 Soldiers and 4 Bikers
(b) 4 Soldiers and 2 Bikers
(c) 2 Soldiers and 4 Bikers
(d) 2 Soldiers and 2 Bikers
(v) What should be added with the numbers of CRPF soldiers and the number of bikers so that t
maximum number of column is equal to the maximum number of column of army troop?
(a) 4 Soldiers and 4 Bikers
(b) 12 Soldiers and 12 Bikers
(c) 6 Soldiers and 6 Bikers
(d) 12 Soldiers and 6 Biker.
​

Answer 1

Given :  

Army contingent of 624 members behind an army band of 32 members.

CRPF troops with 468 soldiers behind the 228 members of bikers.

To Find :  maximum number of columns in which the army troop can march?

maximum number of columns in which the CRPF troop can march?

maximum number of columns in which total army troop and CRPF troop together can march past?

(iv) What should be subtracted with the numbers of CRPF soldiers and the number of bikers so that

their maximum number of column is equal to the maximum number of column of army troop?

(v) What should be added with the numbers of CRPF soldiers and the number of bikers so that their

maximum number of column is equal to the maximum number of column of army troop?

Solution:

army troop

624

32

HCF of 624 and 32

624 = 32 x 19  + 16

32 = 16 x 2  + 0

16 is the HCF

maximum number of columns in which the army troop can march = 16

CRPF troop

468

228

HCF

468 = 228 x 2 + 12

228 = 19 x 12   +  0

12 is the HCF

maximum number of columns in which the CRPF troop can march =  4

HCF of 12 and 16

16 = 12 x 1 + 4

12 = 4 x 3 + 0

4 is HCF

maximum number of columns in which total army troop and CRPF troop together can march  = 4

468 = 16 x 29 + 4

228  = 16 x 14  + 4

Hence  4 numbers of CRPF soldiers and the number of bikers should be subtracted so that their maximum number of column is equal to the maximum number of column of army troop

(a) 4 Soldiers and 4 Bikers

468 = 16 x 30 -  12

228  = 16 x 15  - 12

Hence  12 numbers of CRPF soldiers and the number of bikers should be added so that their maximum number of column is equal to the maximum number of column of army troop

(b) 12 Soldiers and 12 Bikers

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Answer 2

Step-by-step explanation:

(iv) What should be added with the numbers of CRPF soldiers and the number of bikers so t

their maximum number of column is equal to the maximum number of column of army troop

(a) 4 Soldiers and 4 Bikers

(b) 4 Soldiers and 2 Bikers

(c) 2 Soldiers and 4 Bikers

(d) 2 Soldiers and 2 Bikers

(v) What should be added with the numbers of CRPF soldiers and the number of bikers so that t

maximum number of column is equal to the maximum number of column of army troop?

(a) 4 Soldiers and 4 Bikers

(b) 12 Soldiers and 12 Bikers

(c) 6 Soldiers and 6 Bikers

(d) 12 Soldiers and 6 Biker.