Question

(IV) (x + 2) (x + 3) + (x - 3)(x - 2) - 2x (x + 1) = 0​

Answer 1

Step-by-step explanation:

$( {x}^{2} + 3x + 2x + 6) + ( {x}^{2} - 2x - 3x + 6) - {2x}^{2} - 1 = 0$

${x}^{2} + 5x + 6 + {x}^{2} - 5x + 6 - 2 {x}^{2} - 1$

${4x}^{2} + 12 - 1$