Question

(iv) (x + 2)= x? – 4.​

Answer 1

Answer:

x + 2 = x - 4

x = - 4 - 2

x=-6

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Answer 2

Here,LHS =

${(x + 2)}^{2} = {(x + 2)}^{2} {(x + 2)}^{2}$

$= ( {x}^{2} + 4x + 4)(x + 2)$

$= {x}^{3} + {2x}^{2} + {4x}^{2} + 8x + 4x + 8$

$= {x}^{3} + {6x}^{2} + 12x + 8$

Therefore,

${(x + 2)}^{2} = {x}^{3} - 4$

Can be rewritten as

${x}^{3} + {6x}^{2} + 12x + 8 = {x}^{3} - 4$

i.e.,

${6x}^{2} + 12x + 12 = 0$

or,

${x}^{2} + 2x + 2 = 0$

It is in the form of=

${ax}^{2} + 2x + 2 = 0$

${ax}^{2} + bx + c = 0.$

So,the given equation is a quadratic equation.