(iv) x = cot 0 + tan ; y = sec 0 - cos 0
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Answer:
Answer
(
tanθ
1
)+tanθ=x, (
cosθ
1
)+cosθ=y
or
tanθ
sec
2
θ
=x,
cosθ
sin
2
θ
=y.
x=
sinθcosθ
1
, y=
cosθ
sin
2
θ
∴x
2
y=
cos
3
θ
1
=sec
3
θ, x
2
y=tan
3
θ
Since sec
2
θ−tan
2
θ=1
∴(x
2
y)
3
2
−(xy
2
)
3
2
=1
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