Question

(iv) x = cot 0 + tan ; y = sec 0 - cos 0​

Answer 1

Answer:

Answer

(

tanθ

1

)+tanθ=x, (

cosθ

1

)+cosθ=y

or

tanθ

sec

2

θ

=x,

cosθ

sin

2

θ

=y.

x=

sinθcosθ

1

, y=

cosθ

sin

2

θ

∴x

2

y=

cos

3

θ

1

=sec

3

θ, x

2

y=tan

3

θ

Since sec

2

θ−tan

2

θ=1

∴(x

2

y)

3

2

−(xy

2

)

3

2

=1