Question

iv. (x - y)(x + y) = x2 - y2
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Answer 1

Answer:

It is actually an identity

(a+b) (a-b) =a^2-b^2

(x+y) (x-y) = x^2-y^2

x^2-y^2=x^2-y^2

x^2-y^2-x^2+y^2=0

Answer 2

Answer:

(x-y)(x+y) = x^2 -y^2

now, x^2 - y^2 = (x+y)(x-y) algebraic identity

so,

(x-y) (x+y) will be equal to x^2 - y^2

x^2 -y^2 =x^2 - y^2

cut x^2 - y^2 from both the sides

ans will be 0

=0

thank you