(iv) (x² – 2x +3) (x2 – 2x +5) - 35
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let x2-2x=y
assume it to make it easier or else it will be a biquadratic equation
then just get the equation
which comes to be
y2+8y-20=0
after solving the equation you will get 2 roots of equation in terms of y. which are
(y-2)(y+10)=0
so y=2 or -10
Earlier we assumed y to be x2-2x
now put y=x2-2x and solve for 2 and -10
and you will get 4 values of x
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