Question

(iv) (y2-4) (y-1)
solution plz ​

Answer 1

Answer:

(y2-4)(y-1)=0

(y2-2^2)(y-1)=0

(y+2)(y-2)(y-1)=0

y= -2, 2, 1

Step-by-step explanation:

I think it is helpful for you

Answer 2

Answer:

Step-by-step explanation:

y²-4y-1=0

using quadratic formula:

a = 1, b = -4, c = -1

∴  D = b² - 4ac = (-4)² - 4(1)(-1) = 20

20<0 in this case, the roots are real and distinct

let roots of given equation be α and β

α = -b+√d/2a

⇒ α = 4 + 2√2 / 2 =2(2+√2)/2= 2+√2

β = -b-√d/2a

⇒ β = 4 - 2√2 / 2 =2(2-√2)/2= 2-√2

hence roots of equation are 2+√2, 2-√2