Question

(iv) यदि sec 50 = cosec (e-36°), जहाँ 50 एक न्यूनकोण है, तो 6 का मान निकालि
सिद्ध कीजिए कि:​

Answer 1

$\theta = 76$

Step-by-step explanation:

$\sec(50) = \cosec( \theta - 36 ) \\ \\ \sec(90 - 40) = \cosec( \theta - 36 ) \\ \\ \cosec(40) = \cosec( \theta - 36 ) \\ \\ cosec \: को \: cosec \: से \: काट \: दो \\ \\ 40 = \theta - 36 \\ \\ 40 + 36 = \theta \\ \\ \theta = 76$

.

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Answer 2

Step-by-step explanation:

\begin{gathered} \sec(50) = \cosec( \theta - 36 ) \\ \\ \sec(90 - 40) = \cosec( \theta - 36 ) \\ \\ \cosec(40) = \cosec( \theta - 36 ) \\ \\ cosec \: को \: cosec \: से \: काट \: दो \\ \\ 40 = \theta - 36 \\ \\ 40 + 36 = \theta \\ \\ \theta = 76\end{gathered}

sec(50)=cosec(θ−36)

sec(90−40)=cosec(θ−36)

cosec(40)=cosec(θ−36)

cosecकोcosecसेकाटदो

40=θ−36

40+36=θ

θ=76