Question

ive years ago A was thrice as old as B and ten years later A shall be twice as old as B. What are the present ages of A and B? ​

Answer 1

Answer:

Let the present age of B and A be x years and y years respectively.

Then,

B's age 5 years ago = (x-5) years

And A's age 5 years ago = (y-5) years.

Therefore, (y-5) =3(x-5) =>3x-y =10. - - - - - - - (1)

B's age 10 years hence = (x+10)years.

A's age 10 years hence = (y+10) years.

Therefore, (y+10)=2(x+10)=> 2x-y = - 10. ---------(2)

On subtracting (2)from (1),we get, x=20.

Putting x=20 in (1),we get

(3*20)-y =10 =>y=50.

Therefore, x =20 and y =50.

Hence, B's present age =20 years

And, A' s present age =50 years.

Answer 2

HERE IS YOUR ANSWER

Let the age of A be a, and age of B be b

Let the age of A be a, and age of B be bNow, a−5=3(b−5)

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)From 1 and 2,

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)From 1 and 2,3b−10=2b+10

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)From 1 and 2,3b−10=2b+10b=20

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)From 1 and 2,3b−10=2b+10b=20And, a=2b+10=2×20+10=50 years

Let the age of A be a, and age of B be bNow, a−5=3(b−5)a=3b−10 (1)After 10 years,a+10=2(b+10)a=2b+10 (2)From 1 and 2,3b−10=2b+10b=20And, a=2b+10=2×20+10=50 yearsThus, age of A = 50 years and age of B = 20 years.

Hope my answers helps U

Hope my answers helps U THNXS