Question

ive years ago the age of samyak
was four times the age of his two children if twice the present age of samyak is thirteen years less than five times the sum of present age of his two children then after seven years the age of samyak will be​

Answer 1

Answer:

A is samyak and B is there son.

Step-by-step explanation:

Let us consider B’s age = X

Then A’s age = 4X

Five years ago

⇒ A’s age = 4X + 5

⇒ B’s age = X + 5

Five years hence

⇒ A’s age = 4X + 5 + 5

⇒ A’s age = 4X + 10

⇒ B’s age = X + 5 + 5

⇒ B’s age = X + 10

From the given question

4X + 10 = 2(X + 10)

4X + 10 = 2X + 20

4X – 2X = 10

2X = 10

X = 5

A’s age = 4X + 5

A’s age = 25 years

B’s age = X + 5

B’s age = 10 years.