Question

ivide the number 128 into three parts such that the 2nd part is twice the 1st and 3rd part is 7 less than the 2nd part. Which is the 3rd part? *

Answer 1

Answer:

the third part is 47

Step-by-step explanation:

the 1rst part is 27

then multiply it by 2 and you get 54 for the second part

and to get the 3rd part subtract 54-7= 47

   27+54= 81+47= 128

 

Answer 2

Answer:

The value of the 3rd part is 45.

Step-by-step explanation:

Given,

The number (N) = 128 is divided into three parts x, y, and z.

y = 2x, and z = y - 7

To find,

The value of the third part (z).

Calculation,

As N = 128

But N = x + y + z

So, x + y + z = 128...(1)

Also y = 2x, and z = y - 7 = 2x - 7

Now substitute y = 2x, and z = 2x - 7 in equation (1):

x + 2x + 2x - 7 = 128.

⇒ 5x - 7 = 128

⇒ 5x = 135

⇒ x = 27

Hence, z = 2x - 7 = 2(27) - 7 = 45

⇒ z = 45

Therefore, the value of the 3rd part is 45.

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