Iwo bulbs of 500 W and 200 W rated at
250 V will have resistance ratio as
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Here is ur answer,
V=250v(given for both)
P1=500watt,P2=200 Watt
V1=250v,V2=250v
we know that, [P=V^2/R]
now, resistance of 1st bulb ,
P1=V1^2/R1
500=250*250/R1
R1= 125ohm
resistance of 2nd bulb
P2=V2^2/R2
200=200*200/R2
R2=200ohm
therefore ,the ratio of their resistance is R1/R2=125/200=5/8
5:8
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