Math, asked by sayedahad786, 9 days ago

. Iwo ropes of lengths 16 m and 24 m are to be cut into small pieces of equal lengths. What will be the maximum length of each piece?​

Answers

Answered by dharmanikita
1

Answer:

8 m

Step-by-step explanation:

Given:

Length of the first rope = 16 m

Length of second rope = 24 m

Question: "The ropes are to be cut into small pieces of equal lengths. Find the maximum length of each piece."

Solution:

Maximum length of each piece

= HCF of 16 m and 24 m

= 8 m

Therefore, the maximum length of each piece will be 8 m

Answered by wwwaimanichojan
0

Length of 1st rope = 16m

Length of 2nd rope = 24 m

Maximum of length of each piece

= H.C.F of 16 and 24

= 8

Ans : 8m

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