. Iwo ropes of lengths 16 m and 24 m are to be cut into small pieces of equal lengths. What will be the maximum length of each piece?
Answers
Answered by
1
Answer:
8 m
Step-by-step explanation:
Given:
Length of the first rope = 16 m
Length of second rope = 24 m
Question: "The ropes are to be cut into small pieces of equal lengths. Find the maximum length of each piece."
Solution:
Maximum length of each piece
= HCF of 16 m and 24 m
= 8 m
Therefore, the maximum length of each piece will be 8 m
Answered by
0
Length of 1st rope = 16m
Length of 2nd rope = 24 m
Maximum of length of each piece
= H.C.F of 16 and 24
= 8
Ans : 8m
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