Question

ix. 30° more than one-half of its complement
If thelon (1
nalon​

Answer 1

Answer:

Let the required angle be x

Complement of x is (90

o

−x)

According to the question,

x=

2

1

×(90

o

−x)+30

o

⇒ 2x=(90

o

−x)+60

o

⇒ 3x=150

o

⇒ x=

3

150

o

⇒ x=50

o