Math, asked by Harshprabhu, 11 months ago

ix) (a + b)2 + (aw + bw2)2 + (aw2 + bw)2 =
6ab​

Answers

Answered by rajwantkaur123
2

Answer:

2a+2b+6aw+6bw

Step-by-step explanation:

2(a+b)+2(aw+2bw)+2(2aw+bw)

multiplying

2a+2b +2aw + 4bw +4aw+2bw

2a+2b+2aw+4aw+4bw+2bw

add aw ,

then

add bw

2a+2b+6aw+6bw

Similar questions