Question

ix)
An object is falling freely under the
gravitational force. Its velocity after
travelling a distance h is v. If v depends
upon gravitational acceleration g and
distance, prove with dimensional
analysis that v=k gh where k is a
constant​

Answer 1

Answer:

just 5, I have a look at the moment, but I think I have a look at the moment

Answer 2

Applying equations of motions

At first initial velocity = 0(because it fell from the maximum height)

Then it fall due to acceleration due to gravity

Where

S = ut + 1/2 at^2

Here

h = 1/2 gt^2

Also

v^2 - u^2 = 2as

I.e.

v^2 = 2g h

v = (2gh)^1/2

v^2 = 2gh

Where 2 = k