Question

(ix) (cosec A - sin A)(sec A - cos A) = 1/tan A + cot A
[Hint: Simplify LHS and RHS separately]
​

Answer 1

Answer:

Step-by-step explanation:

(1/sin-sin)(1/cos-cos)

(1-sin^2/sin)(1-cos^2/cos)

(Cos^2/sin)(sin^2/cos)

Cos.sin........(LHS)

1/sin/cos+cos/sin

1/sin^2+cos^2/cos.sin

1/1/cos.sin

Cos.sin......(rhs)

Hence proved

LHS=RHS