Question

(ix) (cosec A - sin A)(sec A - cos A) =
tan A + cot A
[Hint: Simplify LHS and RHS separately]


please solve it step by step... don't copy from internet​

Answer 1

Answer:

here is your answer dude

Step-by-step explanation:

ANSWER

LHS=(cosecA−sinA)(secA−cosA)=(

sinA

1

−sinA)(

cosA

1

−cosA)

=(

sinA

1−sin

2

A

)(

cosA

1−cos

2

A

)=sinAcosA=

2

1

sin2A

RHS=

tanA+cotA

1

=

1+tan

2

A

tanA

=

2

1

sin2A

LHS=RHS

Hence Proved

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thanks my answer

Answer 2

Answer:

do this question by yourself I am also weak in this type of questios