Math, asked by jaynandsharma1970, 11 months ago

ix.
viii.
110°
1350
Fig. 8​

Answers

Answered by anku3842
0

Answer:

∠PQT+∠PQR=180

(Straight angle made on line TR at point Q)

110

+∠PQR=180

∠PQR=180

−110

=70

In △PQR

∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles)

135

=70

+∠PRQ

∠PRQ=135

−70

=65

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