Ix year ago parvez's age was same as the present age of manish. If the present age of parvez is one-fourth more than that of manish's present age, then in how many years will parvez's age become double of manish's present age?
Answers
let the age of parvez be x and the age of Manish be y.
then,
9 years ago,
i.e., x-9 = y
presently,
i.e., x = 1/4y
x-9 = y. x = 1/4y
x-y = 9. x-1/4y = 0
It seems minor mistake in the question,
Correct Question :
Six year ago parvez's age was same as the present age of manish. If the present age of parvez is one-fourth more than that of manish's present age, then in how many years will parvez's age become double of manish's present age?
Given :
- Six year ago Parvez’s age was same as the present age of Manish.
- The present age of Parvez is one-fourth more than that of Manish's present age.
To find :
- Pravez's age will become double Manish's present age =?
Step-by-step explanation :
Let, the present age of Manish's be, x
Then the present age of Parvez's be, y.
As per question,
The present age of Parvez is one-fourth more than that of Manish's present age,
•°• Pravez's age = x/4 + x = 5x/4
According to the question,
y - 6 = x
5x/4 = x + 6
x/4 = 6
x = 24.
Therefore, the present age of Manish's, x = 24 years.
And, the present age of Parvez's,
= 5x/4
= 5 × 24/4
= 30 year's
Now,
Pravez's age will become double Manish's present age,
So, Let, the time be, n
As per question,
30 + n = 2(24)
30 + n = 48
n = 48 - 30
n = 18.
Hence, After 18 years, Pravez's age will become double Manish's present age