Math, asked by hritikd4987, 1 year ago

Ix year ago parvez's age was same as the present age of manish. If the present age of parvez is one-fourth more than that of manish's present age, then in how many years will parvez's age become double of manish's present age?

Answers

Answered by AbhishMehra41
0

let the age of parvez be x and the age of Manish be y.

then,

9 years ago,

i.e., x-9 = y

presently,

i.e., x = 1/4y

x-9 = y. x = 1/4y

x-y = 9. x-1/4y = 0

Answered by BrainlyRaaz
50

It seems minor mistake in the question,

Correct Question :

Six year ago parvez's age was same as the present age of manish. If the present age of parvez is one-fourth more than that of manish's present age, then in how many years will parvez's age become double of manish's present age?

Given :

  • Six year ago Parvez’s age was same as the present age of Manish.
  • The present age of Parvez is one-fourth more than that of Manish's present age.

To find :

  • Pravez's age will become double Manish's present age =?

Step-by-step explanation :

Let, the present age of Manish's be, x

Then the present age of Parvez's be, y.

As per question,

The present age of Parvez is one-fourth more than that of Manish's present age,

•°• Pravez's age = x/4 + x = 5x/4

According to the question,

y - 6 = x

5x/4 = x + 6

x/4 = 6

x = 24.

Therefore, the present age of Manish's, x = 24 years.

And, the present age of Parvez's,

= 5x/4

= 5 × 24/4

= 30 year's

Now,

Pravez's age will become double Manish's present age,

So, Let, the time be, n

As per question,

30 + n = 2(24)

30 + n = 48

n = 48 - 30

n = 18.

Hence, After 18 years, Pravez's age will become double Manish's present age

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