IxI^2- 3 IxI+2= 0
FIND THE NUMBER OF REAL SOLUTION OF THE ABOVE GIVEN EQUATION ?
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the number of real solution will be 1 and 2
see this,
x²-3x+2=0
x²-x-2x+2=0
x(x-1)-2(x-1)=0
(x-2)(x-1)=0
x=2 or 1
see this,
x²-3x+2=0
x²-x-2x+2=0
x(x-1)-2(x-1)=0
(x-2)(x-1)=0
x=2 or 1
Satwatneyearthian:
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question is having modx
IxI
SO 2 eq. will be formed
hence 4 solution
nope
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