Question

iy) A side of an isosceles right angled triangle is x find hypotenuse.
​

Answer 1

Answer:

$let \: the \: length \: of \: hypotenus \: be \: y. \: by \: \: using \: the \: pytagoras \: theroum \: of \: triangle \: \\ perpendicular = base = x \\( x) {}^{2} + (x) {}^{2} = (y) {}^{2} \\ 2(x) {}^{2} = (y) {}^{2} \\ \sqrt{2} x = y$

mark me as a brainlist