Iyore and Tigir were carrying honey pots for their friend Winny’s birthday. Lazy Iyore complained that his load is much too heavy. Smart and energetic Tigir jumps around with his pots. Iyore teases Tigir that if he gives one of his pots to Tigir, Tigir would have twice the load he is carrying. Tigir hops around a bit and figures out that if he gave one of his pots to Iyore, they will both be carrying an even amount. What is the minimum number of honey pots, Tigir is carrying for his friend Winny?
a)5
b)6
c)7
d)8
Answers
Answered by
0
Answer:
7 because if Iyore gives tiger 1 pot it becomes twice of him
now let pots ioyer is carrying be x
so x-1 pots with ioyer and 7+1 pot with tiger which means 8
so 2x=8
x=4
as ioyer had gave on pot so he is carrying x+1=5
now if tiger gave 1 pot he will have 6 pots and ioyer will also have 6 pots
Answered by
0
Answer:
5
Step-by-step explanation:
Tigir = 5
Iyore = 3
5+1=2(3)
5-1=3+1=4
ATB for V.O.T.E, I know it is from there..
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