Question

J+1
(iv) p(x) = (x-1)(x+1)​

Answer 1

Question :

Find the zeros of the given quadratic polynomial .

Answer :

x = ± 1

Note:

★ The possible values of the variable for which the polynomial becomes zero are called its zeros .

★ A quadratic polynomial can have atmost two zeros .

Solution :

• Given : p(x) = (x-1)(x+1)
• To find : Zeros of p(x)

We have ,

p(x) = (x-1)(x+1)

In order to find the zeros of the given polynomial p(x) , let's operate on p(x) = 0 .

=> p(x) = 0

=> (x + 1)(x - 1) = 0

=> Either (x + 1) = 0 OR (x - 1) = 0

Case1 : If (x + 1) = 0

=> x + 1 = 0

=> x = - 1

Case2 : If (x - 1) = 0

=> x - 1 = 0

=> x = 1

Hence ,

The zeros of the given polynomial p(x) are ; x = ± 1 .