Question

J=15,24,33,42,51,60 Write in set builder form

Answer 1

HELLO DEAR,

Given: J= (15,24,33,42,51,60)

To write above set in set builder form.

Solution: we can write above set in set builder form,

J= {(15+9n) : n € whole number from

0 to 5}

By putting the value of n from 0 to 5 we get all element or member of set J.

I HOPE IT'S HELP YOU DEAR,

THANKS.

Answer 2

Given:

The set is

J = { 15, 24, 33, 42, 51, 60 }

To find:

The set builder form of the given set J.

Solution:

We have,

J = { 15, 24, 33, 42, 51, 60 }

It is clear that the elements of this set are in AP because the difference between any two consecutive integers is common.

Here, first term is 15 and common difference is 9 .

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

Here, the nth term is defined as

$a_n=15+(n-1)9$

$a_n=15+9n-9$

$a_n=9n+6$

Now, the set builder form of set J is

$J=\{9n+6:n=1,2,3,4,5,6\}$

Therefore, the required set builder form is $J=\{9n+6:n=1,2,3,4,5,6\}$.