Question

J(7,8) K(1,2) L(5,2) The centroid for JKL is at point M. What is JM rounded to the nearest tenth

Answer 1

Answer:

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Answer 2

Answer:  4.6

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Step-by-step explanation:

J(7,8) , K(1,2) , L(5,2)

Centroid of △ =>    $(x,y)=(\frac{x_{1}+x_{2} +x_{3} }{3} ,\frac{y_{1}+y_{2}+y_{3} }{3})$

( x , y ) = $(\frac{7+1+5}{3} ,\frac{8+2+2}{3} )$

M ( x , y ) = $(\frac{13}{3} ,4)$

Distance between points J and M => $\sqrt{(x_{1} -x_{2} )^{2}+(y_{1}-y_{2} )^{2} }$

=>  $\sqrt{(7-\frac{13}{3})^{2}+(8-4)^{2} }$

=>   $\sqrt{(\frac{21-13}{3})^{2}+(4)^{2} }$

=>   $\sqrt{(\frac{8}{3} )^{2} +16 }$

=>   $\sqrt{\frac{64+144}{9} }$

=>    $\sqrt{\frac{208}{9} }$

=>    $\frac{4}{3} \sqrt{13}$

=>     4.6