Question

J
Factorise : 3 y² + 9y + 6​

Answer 1

Answer:

Step-by-step explanation

here's ur answer frend

3y^2+6y+3y+6

=3y(y+2)+3(y+2)

=(y+2) (3y+3)

==> y= -2    OR  y = -1

Answer 2

Answer:

$3 {y}^{2} + 9y + 6 \\ = 3 {y}^{2} + 6y + 3y + 6 \\ = 3y(y + 2) + 3(y + 2) \\ = (3y + 3)(y + 2) \\ therefore \: \\ (3y + 3) = 0 \\ y = - \frac {3}{3} \\ y = - 1 \\ or \\ y + 2 = 0 \\ y = - 2 \\ \\ answer$