Question

J. find the probality of getting
1. at least I head
2. at Jeast I Tail
3. two head
4.Three tail
5.Two head and one tail
6. at most 3 tail


When 3 coins are tossed​

Answer 1

Answer:

1. 7/8

2.7/8

3.3/8

4.1/8

5.3/8

6.7/8

Step-by-step explanation:

S={HHH, HHT, HTH, THH, TTT, TTH, THT, HTT}

n(S) = 8

Event A

A ={HHH, HHT, HTH, THH, TTH,THT,HTT}

n(A) = 7

P(A) = n(A)/n(S)

= 7/8

Event B

B = {HHT, HTH, THH, TTT, TTH, THT, HTT}

n(B) = 7

P(B) = n(B)/n(S)

= 7/8

Event C

C = {HHT, HTH, THH}

n(C) = 3

P(C) = n(C)/n(S)

= 3/8

Event D

D = {TTT}

n(D) = 1

P(D) = n(D)/n(S)

= 1/8

Event E

E = {HHT,HTH, THH}

n(E) = 3

P(E) = n(E)/n(S)

= 3/8

Event F

F = {HHT, HTH, THH, TTT, TTH, THT, HTT}

P(F) = n(F)/n(S)

= 7/8