Question

j) In the given figure, the sides AB and AC of AABC are
produced to points E and D respectively. If the bisectors
BO and CO of ZCBE and ZBCD respectively meet at point
0, then prove that ZBOC = 90° - 1/2 ZBAC.
A
х
B
у
Z
C С
E
D
0​

Answer 1

Answer:

fyfhetette6ruttrudeesguvhgjgashhftadhgujff