j n Mira decided to raise fund for the poor in the neighbourhood they were able to raise funds in the ratio of 6 is to 4 respectively if the person with more fundraise rupees 23.700 1) find the amount raised by the other person and 2)the total amount raised.
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If the ratio of contribution is 6:4, then let us assume the numbers as 6x, 4x.
Let us assume the fund raised as y.
So according to question: 6x+4x = y (Equation 1)
1) Given 6x = 23.700 (Obviously the person raising more fund has the larger ratio)
⇒ 6x = 23.700
⇒ x = 23.700÷6
⇒ x = 3.95 (Equation 2)
By putting the value of equation 2 in equation 1 we calculate the value of 4x i.e.
4x = 4×3.95
⇒ 4x = 15.8
The amount raised by second person is rupees 15.8
2) Total amount raised = y (From equation 1)
⇒ 6x+4x = y
⇒ 23.700 + 15.8 = y
⇒ y = 39.5
The total amount raised is rupees 39.5
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