Question

j) (x + x + 1)(x + 7x + 12)< 0​

Answer 1

Step-by-step explanation:

Given x

2

−7x+12=0

This is in the form ax

2

+bx+c=0 where, a = 1, b = -7 and c = 12

Quadratic formula is, x=

2a

−b±

b

2

−4ac

By substituting the values, we get

x=

2×1

−(−7)±

(−7)

2

−4×1×12

=

2

7±

49−48

=

2

7±

1

=

2

7±1

If x=

2

7+1

=

2

8

=4 x=

2

7−1

=

2

6

=3

∴ 4 and 3 are the roots of x

2

−7x+12=0

Answer 2

Answer:

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