Question

J28² – 6f + 3√2 = 0​

Answer 1

Explanation:

Comparing 2x2 - 5x + 2 = 0 and ax2 + bx + c = 0, we get

a = 2, b = -5 and c = 2

Then,

x = [-b ± √b2 - 4ac] / 2a

x = [-(-5) ± √(-5)2 - 4(2)(2)] / 2(2)

x = [5 ± √(25 - 16)] / 4

x = [5 ± √9] / 4

x = [5 ± 3] / 4

x = (5 + 3) /4 and x = (5 - 3)/4

x = 8/4 and x = 2/4

x = 2 and x = 1/2

Therefore, the solution is {1/2, 2}.

Example 2 :

√2f2 - 6f + 3√2 = 0

Solution :

Comparing √2f2 - 6f + 3√2 = 0 and ax2 + bx + c = 0, we get

a = √2, b = -6 and c = 3√2

Then,

x = [-b ± √b2 - 4ac] / 2a

x = [-(-6) ± √(-6)2 - 4(√2)(3√2)] / 2(√2)

x = [6 ± √(36 - 24)] / 2√2

x = [6 ± √12] / 2√2

x = [6 ± 2√3] / 2√2