Math, asked by ktktdktkt, 1 year ago

j50 points ! fast

solve this 4 no.


anyone????

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Answers

Answered by shadowsabers03
3

       

Let,

ST = u

TU = s

SU = t

a. Using 'Law of Cosines' Formula

   

We need to find s.

s² = t² + u² - 2tu cos S

⇒ s² = 15² + 10² - (2 · 15 · 10 · cos 95°)

⇒ s² ≈ 225 + 100 - (300 ·  - 0.087)

⇒ s² ≈ 325 - (- 26)

⇒ s² ≈ 325 + 26

⇒ s² ≈ 351

⇒ s ≈ √351

⇒ s ≈ 18.73 m

b. Using 'Law of Sines' Formula

   

sin U / u = sin S / s

⇒ sin U / 10 ≈ sin 95° / 18.73

⇒ sin U / 10 ≈ 1 / 18.73

⇒ sin U ≈ 1 / 18.73  ·  10

⇒ sin U ≈ 0.534

⇒ U ≈ sin⁻¹ 0.534

⇒ U ≈ 32.28°

c.

∠T = 180° - (∠S + ∠U)

⇒ ∠T = 180° - (95° + 32.28°)

⇒ ∠T = 180° - 127.28°

⇒ ∠T = 52.72°

Hope this helps. Plz ask me if you've any doubts on my answer.

Thank you. :-))

     


sharmalalit008: Can you tell this is the question of which level or class ??
idkgoodd: 10th icgse
sharmalalit008: Ok
sharmalalit008: Thanks
Answered by Tanujrao36
0

ANSWER:

Length of TU = 18.72m approx.

Angle U = 32.28°

Angle T = 52.72°

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