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solve this 4 no.
anyone????
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Let,
ST = u
TU = s
SU = t
a. Using 'Law of Cosines' Formula
We need to find s.
s² = t² + u² - 2tu cos S
⇒ s² = 15² + 10² - (2 · 15 · 10 · cos 95°)
⇒ s² ≈ 225 + 100 - (300 · - 0.087)
⇒ s² ≈ 325 - (- 26)
⇒ s² ≈ 325 + 26
⇒ s² ≈ 351
⇒ s ≈ √351
⇒ s ≈ 18.73 m
b. Using 'Law of Sines' Formula
sin U / u = sin S / s
⇒ sin U / 10 ≈ sin 95° / 18.73
⇒ sin U / 10 ≈ 1 / 18.73
⇒ sin U ≈ 1 / 18.73 · 10
⇒ sin U ≈ 0.534
⇒ U ≈ sin⁻¹ 0.534
⇒ U ≈ 32.28°
c.
∠T = 180° - (∠S + ∠U)
⇒ ∠T = 180° - (95° + 32.28°)
⇒ ∠T = 180° - 127.28°
⇒ ∠T = 52.72°
Hope this helps. Plz ask me if you've any doubts on my answer.
Thank you. :-))
sharmalalit008:
Can you tell this is the question of which level or class ??
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ANSWER:
Length of TU = 18.72m approx.
Angle U = 32.28°
Angle T = 52.72°
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