Math, asked by maahira17, 1 year ago

जोड़िए :
(i) } 3mn,-5mn,8mn,-4mn \text{ (ii) } t-8tz, 3tz-z, z-t \text{ (iii) } -7mn+5, 12mn+2, 9mn-8, -2mn-3 \text{ (iv) } a+b-3, b-a+3, a-b+3 \text{ (v) } 14x+10y-12xy-13, 18-7x-10y+8xy, 4xy \text{ (vi) } 5m-7n, 3n-4m+2, 2m-3mn-5 \text{ (vii) } 4 x ^{2}y, -3 x y^{2}, -5x y^{2}, 5x^{2} y \text{ (viii) } 3p^{2}q^{2}-4pq+5, -10p^{2}q^{2}, 15+9pq+7 p^{2} q^{2}\text{ (ix) } ab-4a, 4b-ab, 4a-4b \text{ (x) } x^{2}-y^{2}-1, y^{2}-1-x^{2}, 1-x^{2}-y^{2} [/tex]

Answers

Answered by nikitasingh79
3

Step-by-step explanation:

(i) दिया है : 3mn, - 5mn, 8mn, - 4mn  

= 3mn + (- 5mn) + (8mn) +  (- 4mn )

= 3mn  - 5mn +  8mn - 4mn  

= - 2mn + 4mn

= 2mn

 

(ii) दिया है : t – 8tz, 3tz – z, z – t  

= t – 8tz + 3tz – z +  z – t  

= t - t - 8tz + 3tz - z + z

= - 5tz  

 

(iii) दिया है : – 7mn + 5, 12mn + 2, 9mn – 8, – 2mn – 3  

= – 7mn + 5 + 12mn + 2 + 9mn – 8 + (– 2mn – 3)  

= – 7mn + 5 + 12mn + 2 + 9mn – 8 – 2mn - 3

= – 7mn + 12mn + 9mn – 2mn + 5  + 2 -  8 -  3

= – 7mn + 21mn  – 2mn  + 7 - 11

= 14mn - 4  

 

(iv) दिया है : a + b – 3, b – a + 3, a – b + 3  

= a + b – 3 + b – a + 3 + a – b + 3

 = a – a + a + b + b – b – 3 + 3 + 3

= a + b + 3

 

(v) दिया है : 14x + 10y – 12xy – 13, 18 – 7x – 10y + 8xy, 4xy  

= 14x + 10y – 12xy – 13 + 18 – 7x – 10y + 8xy + 4xy  

= 14x - 7x + 10 y - 10 y – 12xy + 8xy + 4xy  – 13 + 18

= 7x + 5

 

(vi) दिया है : 5m – 7n, 3n – 4m + 2, 2m – 3mn – 5  

= 5m – 7n + 3n – 4m + 2 +  2m – 3mn – 5  

= 5m - 4m + 2m - 7n + 3n  – 3mn + 2  – 5  

= 3m - 4n – 3mn - 3

 

(vii) दिया है : 4x² y, - 3xy² , - 5xy² , 5x² y  

= 4x² y + (- 3xy²) + ( - 5xy²) +  5x² y  

= 4x² y - 3xy² - 5xy² +  5x² y  

= 4x² y +  5x² y - 3xy² - 5xy²

=  9x² y -  8xy²

 

(viii) दिया है : 3p²q² – 4pq + 5, – 10 p²q² , 15 + 9pq + 7p²q²

= 3p²q² – 4pq + 5 +  (– 10 p²q²) +  15 + 9pq + 7p²q²

=  3p²q² – 4pq + 5 – 10 p²q² +  15 + 9pq + 7p²q²

= 3p²q² – 10 p²q² + 7p²q² – 4pq + 9pq + 5 +  15  

=  - 7p²q²  + 7p²q² + 5pq + 20

= 5pq + 20

 

(ix) दिया है : ab – 4a, 4b – ab, 4a – 4b

=  ab – 4a + 4b – ab + 4a – 4b

= ab - ab - 4a + 4a + 4b - 4b

= 0

 

(x) दिया है : x² – y² – 1, y² – 1 – x² , 1 – x² – y²

= x² – y² – 1 + y² – 1 – x² + 1 – x² – y²

= x² - x² - x² - y² + y² - y² - 1 - 1 + 1

= - x² - y² - 1

आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।

 

इस पाठ  ( बीजीय व्यंजक ) के सभी प्रश्न उत्तर :  

https://brainly.in/question/13518709#

 

इस पाठ से संबंधित कुछ और प्रश्न :  

निम्नलिखित में समान पदों को छाँटिए : \text{(i) } -xy^{2}, -4 y x^{2}, 8 x^{2}, 2x y^{2), 7y, -11 x^{2}, -100x, -11yx, 20 x^{2}y, -6 x^{2}, y, 2xy, 3x \text{ (ii) }10pq, 7p, 8q, -p^{2} q^{2}, -7 qp, -100q, -23, 12 q^{2} p^{2}, -5 p^{2}, 41, 2405p, 78qp, 13p^{2}q, qp^{2}, 701 p^{2}

https://brainly.in/question/13522276#

 

समान पदों को संयोजित (मिला) करके सरल कीजिए : \text{(i) } 21b-32+7b-20b \text{ (ii) } -z^{2}+13 z^{2}-5z+7 z^{3}-15z \text{ (iii) } p-(p-q)-q-(q-p) \text{ (iv) } 3a-2b-ab-(a-b+ab) +3ab+b-a \text{ (v) } 5 x^{2}y-5 x^{2}+3yx^{2}-3y^{2}+x^{2}-y^{2}+8xy^{2}-3y^{2} \text{ (vi) } (3y^{2}+5y-4)-(8y-y^{2}-4)

https://brainly.in/question/13529602#

Similar questions