Question

Jaanvi borrows rupess 20000 at 12% per annum compound interest. If she repays rupees 8400 at the end of the first year and rupees 9680 at the end of the second year. Find the amount of loan standing at the beginning of the third year.



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Answer 1

Answer:

si=20000*12*1/100=2400

amout=20000+2400=22400

22400-8400=14000

si=14000*12*1/100=1680

am=14000+1680=15680

15680-9680=6000

si=6000*12*1/100=720

amout=6720