jack and mark together, mark and john together can do a work in 45 days and 60 days respectively..if jack is thrice as efficient as john, then find the number of days taken by jack to complete the work?
Answers
Solution :-
given that,
→ Jack = 3 * John
→ Jack/John = 3/1
Let jack completes 3x units and john completes x units daily . also mark mark completes y unit / day.
A/q,
→ 45(Jack + mark) = 60(mark + john)
→ 45(3x + y) = 60(y + x)
→ 135x + 45y = 60x + 60y
→ 135x - 60x = 60y - 45y
→ 70x = 15y
→ x/y = 15/75
→ x/y = 1/5
therefore,
→ Time taken by jack to complete the work = Total work / Efficiency / day = 60(x + y)/3x = 60 * 6/15 = 24 days (Ans)
Learn more :-
Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining wo...
https://brainly.in/question/21025557
Shivam alone can do a work in 12 days and Maanik alone can do it in, 15 days. Both started the work together and after w...
https://brainly.in/question/14687371
Answer:
90 days
Step-by-step explanation: