Question

Jack has a cube with 6 sides numbered 1 through 6. He rolls the cube repeatedly until the first time that the sum of all of his rolls is even, at which time he stops. (note: it is possible to roll the cube just once.) what is the probability that jack will need to roll the cube more than 2 times in order to get an even sum?

Answer 1

Step-by-step explanation:

You can say that the probability that Jack rolls more than twice is 1- Probability Jack rolls once or twice.

Probability Jack rolls once = P(1)=36=12P(1)=36=12

Here is the possible solution of 2 roll even numbers {1,1},{1,3},{1,5},{3,1},{3,3},{3,5}.........{5,5} or 9 combinations out of 36

Probability Jack rolls twice = P(2)=9/36=14P(2)=93/6=14

Probability Jack rolls once or twice= Probability Jack rolls once + Probability Jack rolls twice=12+14=3412+14=34

Hence the probability that Jack rolls more than twice = 1- Probability Jack rolls once or twice =1−34=14

Answer 2

Answer:

When the retreating monsoon blows from the northeast across the Bay of Bengal, it picks up a significant amount of moisture, which is subsequently released after moving back onto the peninsula. ... That rainy extension of the generally dry retreating monsoon is called the northeast, or winter, monsoon.

......