Math, asked by shivanshjadhav2012, 18 days ago

Jack takes 20 minutes to jog around the race course one time, and 25 minutes to jog around a second time. What is his average speed in miles per hour for the whole jog if the course is 3 miles long?
A) 6 B) 8 C) 9 D) 10
EXLANATION NEEDED

Answers

Answered by WildCat7083
27

\huge\ \pmb{\orange{«\: คꈤ \mathfrak Sฬєя \: » }}

B) 8

\begin{gathered}\qquad \longmapsto \frak{\underline{ {\red{ Average  \: speed =  \frac{total  \: distance}{ total  \: time}  }}} } \\\end{gathered}

We are given with:

  • Total distance covered = 6 miles;
  • Total time = 45 minutes = 0.75 hours

 \bold \green{Average \:  speed = \frac{6}{0.75}  = 8 miles/hour}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \: \huge \bold{@WildCat7083 } \\

Answered by BrainlyArnab
2

Answer:

B) 8 miles/hour

Step-by-step explanation:

given -

Rahul jogs 1 round (1st time) = 20 min

Rahul jogs 1 round (2nd time) = 25 min

Rahul jogs both time around the course = 3 mile long

to find -

Rahul's average speed (in kmph)

solution -

average speed = total distance / total time taken

= 2 rounds of 3 miles / 20 min and 25 min

= 6 miles / 45 min

to change into hours

= 6 × 60 miles / 45 hours

= 360 miles / 45 hours

= 8 miles/hour

Hence Rahul's average speed = 8 miles/hour

hope it helps.

Similar questions