Question

Jackson invested rupee 20000.He invested a part of it at 12%and rest at 10% . his annual income from these investment is rup2280. how much did he invest at each rate?




guys pls help. me pls pls ​

Answer 1

Let Jackson invested Rs. x at the rate of interest 12% and remaining amount Rs. (20,000 - x) at the rate of 10%.

According to the question,

12% of x + 10% of (20,000 - x) = 2280

0.12x + 0.1(20,000 - x) = 2280

0.12x + 2000 - 0.1x = 2280

0.02x = 280

x = Rs. 14,000

Jackson invested Rs. 14,000 at 12% and (20,000 - 14,000) = Rs. 6000 at 10%.

Answer 2

$\bf\huge{\red{Question←:}}$

$\bf{\red{:→}}$ Jackson invested rupee 20000.He invested a part of it at 12%and rest at 10% . his annual income from these investment is rup2280. how much did he invest at each rate?

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$\bf\huge{\red{Answer←:}}$

$\bf{\red{:→}}$ Let the money invested by jackson be Rs.x at a rate of interest 12% and the remaining amount be 20,000-x at the rate of 10%.

$\bf{\bold{\red{As~per~the~question,}}}$

$\bf{\red{:→}}$ 12% of x + 10% of (20,000-x) = 2280

$\bf{\red{:→}}$ 0.12x + 0.1(20,000-x) = 2280

$\bf{\red{:→}}$ 0.02x = 280

$\bf{\red{:→}}$ x = ₹14,000

$\bf{\red{:→}}$$\bf{\bold{\red{Jackson~invested=Rs.14,000}}}$ at 12%

$\bf{\red{:→}}$$\bf{\bold{\red{20,000-14,000=Rs.6,000}}}$ at 10%

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