Question

Jadli batoa ans english me fast bhai log 1000 pts ke liye

Answer 1

Answer:

Wrong subject bhai but anyways i will solve

1. (x+5)^2 = 2(5x-3)

= x^2 +10x + 25 = 10x -6

= x^2 + 31

D = b^2 - 4ac

From the given equation,

a = 1 , b= 0, c = 31

D = 0 - 4(1) (31)

D = 124

2.  27/ 2^3 . 5^4. 3^2

this can be written as

3^3/ 2^3 . 5^4 . 3^2

3/ 2^3 . 5^4

Highest power of denominator is 4

Hence, the number will terminate after 4 places of decimal.

           OR

429 = 3 x 11 x 13.

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Hope it helps, if it does pls mark as brainliest :))

Answer 2

Answer:

1. (x+5)^2 = 2(5x-3)

= x^2 +10x + 25 = 10x -6

= x^2 + 31

D = b^2 - 4ac

From the given equation,

a = 1 , b= 0, c = 31

D = 0 - 4(1) (31)

D = 124

2.  27/ 2^3 . 5^4. 3^2

this can be written as

3^3/ 2^3 . 5^4 . 3^2

3/ 2^3 . 5^4

Highest power of denominator is 4

Hence, the number will terminate after 4 places of decimal.