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6
[Co(NH
3
)
4
(H
2
O)Cl]SO
4
In the above compound,
Oxidation state of ammonia, (NH
3
)=0
Oxidation state of water, (H
2
O)=0
Oidation state of chlorine, (Cl)=−1
Oxidation state of sulphate ion, (SO
4
)=−2
Let the oxidation state of cobalt, (Co) be x.
As we know that sum of oxidation states of all atoms is equal to the overall charge on the compound.
∴x+(4×0)+(1×0)+(−1)+(−2)=0
⇒x+0+0−1−2=0
⇒x−3=0
⇒x=+3
Hence, the oxidation state of cobalt, (Co) in the compound [Co(NH
3
)
4
(H
2
O)Cl]SO
4
is +3.
hope it helps u
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