Jagadish has three more rupees 5 coins than rupees 10 coins . If he has rupees 195 worth of money in total , how many of each kind of coins does he have?
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Let coins of ₹10be=x
Then coins of ₹5 =x+3
Therefore 10x+5(x+3) = 195
15x=180
X=12
So Jagdish has 12 coins of ₹10
15 coins of ₹5
Then coins of ₹5 =x+3
Therefore 10x+5(x+3) = 195
15x=180
X=12
So Jagdish has 12 coins of ₹10
15 coins of ₹5
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