Question

Jagbir blended 8 kg of one type of jaggery with 12 KG of another this sold each kg the blended jaggery at a price 50% higher than the cost price of the first type of jaggery per kg and made an overall profit of 25% what is the ratio of the cost price of the first and second type of jaggery

Answer 1

Step-by-step explanation:

Tell Jagbir to learn Maths and solve his own problems.

Answer 2

Answer:

The ratio of the cost price of the first and second type of jaggery is 3 : 4

Step-by-step explanation:

Let x be the cost price per kg of first type of the jaggery and y be the cost price per kg of the second type of jaggery,

Thus, the total cost price of the 8 kg of one type of jaggery with 12 kg of another type = 8x + 12y,

Total jaggery = 8 + 12 = 20 kg,

Now, the selling price of the total jaggery per kg = 150% of x = 1.5x,

Thus, selling price of the jaggery = 1.5x × 20 = 30x,

According to the question,

125% of (8x+12y) = 30x

1.25(8x+12y) = 30x

10x + 15y = 30x

15y = 20x

$\implies \frac{x}{y}=\frac{15}{20}=\frac{3}{4}$

Hence, the ratio of the cost price of the first and second type of jaggery is 3 : 4