Math, asked by abhishekbhalla, 9 months ago

Jagbir blended 8 kg of one type of jaggery with 12 kg of another. He sold each kg of the blended jaggery at a price 50% higher than the cost price of the first type of jaggery per kg and made an overall profit of 25 %. What is the ratio of the cost prices of the first and the second types of jaggery?

Answers

Answered by jitekumar4201
0

Answer:

Ratio of Cost Price of Type 1 and Type 2 Jaggery is,

\frac{3}{4}

Step-by-step explanation:

In the question,

Quantity of Type 1 of Jaggery = 8 kg

Quantity of Type 2 of Jaggery = 12 kg

Total blended Jaggery = 20 kg

Let us say that the Cost Price of the Jaggery of Type 1 is = x Rs./kg

and,

Cost Price of Jaggery of Type 2 = y Rs./kg

Therefore, Cost Price = (8x + 12y)

Selling Price of the Jaggery is 50% higher than the Cost Price of Type 1 Jaggery.

So,

Selling Price, SP is given by,

SP=x+\frac{50}{100}x=x+\frac{x}{2}\\SP=\frac{3x}{2}

Therefore, the Total Selling Price = 20\times \frac{3x}{2}=30x

Profit Made = 25%

So,

Profit\%=\frac{SP-CP}{CP}\times 100\\25=\frac{30x-(8x+12y)}{(8x+12y)}\times 100\\0.25=\frac{22x-12y}{8x+12y}\\2x+3y=22x-12y\\20x=15y\\4x=3y\\\frac{x}{y}=\frac{3}{4}

Therefore, the Ratio of Cost Price of Type 1 and Type 2 Jaggery is,

\frac{3}{4}

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